-9-2=? -2-9=? -2+9=? -9+2=? -2+-9=? -9+-2=? tolong ya
1. -9-2=? -2-9=? -2+9=? -9+2=? -2+-9=? -9+-2=? tolong ya
-9-2=-11 -2-9=-11 -2+9=7 -9+2=-7 -2+-9=-11 -9+-2=-11-9-2=-11. -2-9=-11. -2+9=7. -9+2=-7. -2+-9=-11. -9+-2=-11
2. 9 × 9 + ( 2 ÷ 2( 2 - 2 ) = .....?......
9 × 9 + ( 2 ÷ 2( 2 - 2 )
= 9 × 9 + 1(0)
= 81 + 0
= 81
semoga membantu9 × 9 + (2 ÷ 2(2 - 2))
= 81 + (1(0))
= 81 + 0
= 81
[tex]\huge \boxed{ \bf \purple{Xx} \red{B} \blue{a} \green{d} \orange{G} \purple{i} \red{r} \blue{l} \purple{xX}}[/tex]
#CMIIW
3. Q. -, 9^2 + 9^2 = 9^2 - 5^2 = ._."
Jawab:
162
56
Penjelasan dengan langkah-langkah:
9^2 + 9^2 =
9^2 - 5^2 =
==================
9² + 9²
9 x 9 + 9 x 9
81 + 81
162
9² - 5²
9 x 9 - 5 x 5
81 - 25
56
Jawaban:
9^2 + 9^2 = 162
9^2 - 5^2 = 56
9²=8×8=81
81+81=162
9²=8×8=81
5²=5×5=25
81 - 25 = 56
4. (2/9:2)+2 4/9 [tex](2 \9 \div 2) + 24 \9[/tex]
Jawaban:
[tex]( \frac{2}{9} \div 2) + \frac{24}{9} \\ = ( \frac{2}{9} \times \frac{1}{2} ) + \frac{24}{9} \\ = \frac{2}{18} + \frac{24}{9 } \\ = \frac{2 + 48}{18} \\ = \frac{50}{18} \\ = 2 \frac{14}{18} \\ = 2 \frac{7}{9} [/tex]
kalau bener follow + jadikan yang tercedas ya
kalau salah maaf ya
I NEVER COPY ANYONE'S ANSWERS
[tex]( \frac{2}{9} \div 2) + 2 \frac{4}{9} \\ = ( \frac{4}{18} \div 2) + 2 \frac{4}{9} \\ = \frac{1}{9} + 2 \frac{4}{9} \\ = \frac{1 + 22}{9} \\ = \frac{23}{9} \\ = 2 \frac{5}{9} [/tex]
5. nilai dari 2^13-2^9+2^11-2^7+2^9-2^5/2^9+2^7+2^5
(2^13-2^9+2^11-2^7+2^9-2^5)/(2^9+2^7+2^5)
= (2^13- 2^9 + 2^9 + 2^11 - 2^7- 2^5) / (2^5 (2^4 + 2^3 + 1))
= (2^5 (2^8 + 2^6 - 2² - 1)) / (2^5 (2^4 + 2^3 + 1))
= (256 + 64 - 2 - 1) / (16 + 8 + 1)
= 317 / 25
= 12 17/25
Kelas 9
Pelajaran Matematika
Bab 5 Akar dan Pangkat
Kata kunci : -
Kode kategorisasi : 9.2.5
Internal link
https://brainly.co.id/tugas/11151717
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Hai, Salam Kenal!!*^▁^*Yuk Bahas Soal!
✅Pembahasan
• 2^13 - 2^9 + 2^11 - 2^7 + 2^9 - 2^5 / 2^9 + 2^7 + 2^5
• 8.192 + 512 + 2.048 - 128 + 512 - 32/512 + 128 + 32
• 10.080/672
• 15
Semoga Membantu*^▁^*
✅Matematika
✅Tetap Semangat Belajar!
✅Jangan Menyerah!
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6. (2/9 : 2) + 2 4 / 9=berapa?
Penjelasan dengan langkah-langkah:
[tex]( \frac{2}{9} \div 2) + 2 \frac{4}{9} \\ = ( \frac{2}{9} \times \frac{1}{2} ) + 2 \frac{4}{9} \\ = \frac{1}{9} + 2 \frac{4}{9} \\ = 2 \frac{5}{9} [/tex]
7. Q. Perpangkatan 9³ + 9⁴ - 9⁴ = ? 2⁴ - 2³ + 2⁴ = ?
[tex] \boxed{\boxed{\red{\mathcal{JAWABAN}}}}[/tex]
Soal pertama→ 9³ + 9⁴ - 9⁴
→ (9×9×9) + (9×9×9×9) - (9×9×9×9)
→ 729 + 6.561 - 6.561
→ 7.290 - 6.561
→ 729
Soal kedua→ 2⁴ - 2³ + 2⁴
→ (2×2×2×2) - (2×2×2) + (2×2×2×2)
→ 16 - 8 + 16
→ 8 + 16
→ 24
–Stacia
Jawaban:
9³ + 9⁴ -9⁴
(9×9×9) + (9×9×9×9) - (9×9×9×9)
729 + 6.561 - 6.561
= 7292⁴ - 2³ + 2⁴
(2×2×2×2) - (2×2×2) + (2×2×2×2)
16 - 8 + 16
= 24Penjelasan dengan langkah-langkah:
Makasih kak
8. Quiz!! #7 - #Tak terhingga 2 + 2 - 2 × 2 = ... 9 × 9 × 9 = ...
Jawaban☆
1.) 0
2.) 729
_____________________ ☞ No 1 ☜1.) 2 + 2 - 2 × 2
=> 2 + 2 - ( 2 × 2 )
=> 4 - 4
=> 0
☞ No 2 ☜2.) 9 × 9 × 9
=> ( 9 × 9 ) × 9
=> 81 × 9
=> 729
•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•
#CMIIW
Jawaban:
1) 0
2) 729
PenyelesaianKerjakan dari perkaliannya lebih dulu~
1.) 2 + 2 - 2 × 2 = ...
= 2 + 2 - (2 × 2)
= 2 + 2 - 4
= 4 - 4
= 0
2.) 9 × 9 × 9 = ...
= 81 × 9
= 729
9. Look at this math steps.[tex]2 + 2 = 4 \\ = 4 - \frac{9}{2} + \frac{9}{2} \\ = \sqrt{ {(4 - \frac{9}{2})}^{2} } + \frac{9}{2} \\ = \sqrt{ {4}^{2} - 2 \times 4 \times \frac{9}{2} + {( \frac{9}{2}) }^{2} } + \frac{9}{2} \\ = \sqrt{16 -36 + {( \frac{9}{2}) }^{2} } + \frac{9}{2} \\ = \sqrt{ - 20 + {( \frac{9}{2}) }^{2} } + \frac{9}{2} \\ = \sqrt{25 - 45 + {( \frac{9}{2}) }^{2} } + \frac{9}{2} \\ = \sqrt{ {5}^{2} - 2 \times 5 \times \frac{9}{2} + {( \frac{9}{2}) }^{2} } + \frac{9}{2} \\ = \sqrt{ {(5 - \frac{9}{2})}^{2} } + \frac{9}{2} \\ = 5 - \frac{9}{2} + \frac{9}{2} \\ = 5[/tex]The conclusion is 2 + 2 = 5.At which step does it have significant flaw? Explain.
Answer:
The problem is when you convert 4 – 9/2 to √(4 – 9/2)². You actually change it from negative value to positive value.
Explanation:
We should not get confused of these 2 things
x² = ...
and
√(x)² = ...
When we use x², the value of x could be either positive or negative, but when we use √(x)² the value of x would be always positive. This is the basic principal in math.
So now we check that
4 – 9/2 = -0,5 (it is negative)
And
5 – 9/2 = 0,5 (it is positive)
So at the beginning we actually have the negative form of 0,5. Then, we square it so that at the end we find the square root is the positive form of 0,5.
If we could pick the negative form of 5 – 9/2 (it means 9/2 – 5 which equals to -0,5), then we would have consistent calculation.
2 + 2 = -(5 – 9/2) + 9/2
2 + 2 = 9/2 - 5 + 9/2
2 + 2 = 9 - 5
2 + 2 = 4
But we can’t use 9/2 – 5 as the square root of √(5 – 9/2)² since it will break the basic math principle. So here we get a conclusion that we should not change a number (x) into square root form (√(x)²) since it would change it from negative form to positive form.
Learn more:
1. Material about quadratic equation https://brainly.co.id/tugas/9997633
2. Material about quadratic equation https://brainly.co.id/tugas/9982661
3. Material about identifying the coefficients of quadratic equation https://brainly.co.id/tugas/9990588
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Details
Grade : 8
Subject : Math
Chapter : Chapter 6 – Quadratic Equation
Code : 8.2.6
Keywords : root, square
10. (√9-√2) (√9-√2)=..... (2√3-√2) (2√3-√2)=.....
(√9-√2) (√9-√2)=
9-√18-√18+2
11-2√18
11-6√2
(2√3+√2) (2√3+√2)=
4√9+2√6+26+√4
4.3+2√6+2√6+2
14+4√6
11. ( 2/9 : 2 ) + 2 4/9 =
Jawaban:
Ada di gambar
Semoga membantu ^_^
12. Penyelesaian dari 2|3-2x|-6 ≥ 18 adalah … A.-9/2≤x≤15/2 B.x≤- 9/2 atau x≥15/2 C -9/2≤x≤9/2 D.-15/2≤x≤9/2 E.x ≤- 15/2 atau x ≥ 9/2
2|3-2x|-6 >= 18
6-4x >= 18+6
6-4x >= 24
•6-4x >= 24
-4x >= 24-6
-4x >= 18
x >= -18/4
x >= -9/2
•6-4x <= -24
-4x <= -24-6
-4x <= -30
x <= -30/-4
x <= 15/2
jadi jawabannya: B
Jawab:
Penjelasan dengan langkah-langkah:
Pertidak samaan harga mutlak.
2| 3 - 2x | - 6 ≥ 18
2| 3 - 2x | ≥ 18 + 6
2 | 3 - 2x | ≥ 24
| 3 - 2x | ≥ 24/2
| 3 - 2x | ≥ 12
3 - 2x ≤ -12
-2x ≤ -12 - 3
-2x ≤ - 15
2x ≥ 15
x ≥ 15/2
atau
3 - 2x ≥ 12
-2x ≥ 12 - 3
-2x ≥ 9
2x ≤ -9
x ≤ -9/2
Hp = { x | x ≤ -9/2 atau x ≥ 15/2 }
opsi pilihan ( B )
semoga bisa membantu
13. (-2/9)³×(-2/9)⁷÷(-2/9)⁹ berapa kah jawabannya?
Jawaban:
Ada Angka pastinya jawabannya
Penjelasan dengan langkah-langkah:
Gak salah kan.logikanya
14. Sederhanakan ( -2/9)³ × ( -2/9)⁷ : ( -2/9)⁹
dimisalkan (-2/9) = a
maka [tex]a^3 . a^7 : a^9 = a^3^+^7^-^9 = a^\\[/tex]
= -2/9
15. Quiz.Nih yg lebih gampang ^_^[tex] {9}^{2} + {9}^{2} + {9}^{2} + {9}^{2} + {9}^{2} + {9}^{2} + {9}^{2} + {9}^{2} + {9}^{2} = {9}^{n} [/tex]n = ....??klo tau cara yg gampang silahkan, tapi klo mau pke cara yg ribet juga gk apa".
Jawaban:
9^3
nilai n ≈ 3
Penjelasan dengan langkah-langkah:
penjumlahan 9^2 sebanyak 9 kali, maka 9 × (9^2)9^2 + 9^2 + 9^2 + 9^2 + 9^2 + 9^2 + 9^2 + 9^2 + 9^2
= 9 × (9^2)
= 9^1 × 9^2
= 9^(1+2)
= 9^3
maka, nilai n adalah 3
PendahuluanBilangan Eksponen adalah sebuah bilangan yang diartikan sebagai perkalian berulang dari bilangan yang di pangkatkan tersebut dan menghasilkan bilangan berpangkat.
Rumus bilangan eksponen :
[tex] \sf {a}^{m} \times {a}^{n} = {a}^{m + n} [/tex]
ket :
a = bilangan pokok
m dan n = bilangan pangkat
Contohnya :
[tex] \boxed{ \sf {5}^{6} \times {5}^{4} = {5}^{6 + 4} = {5}^{10}}[/tex]
[tex] \boxed{ \sf{ {5}^{6} \div {5}^{4} = {5}^{6 - 4} = {5}^{2}}} [/tex]
Pembahasan9² + 9² + 9² + 9² + 9² + 9² + 9² + 9² + 9²
= 9 × 9²
= 9¹ × ²
= 9^(1+2)
= 9³
KesimpulanJadi, hasilnya adalah 9³
Pelajari Lebih Lanjut1. Pengertian bilangan eksponen
brainly.co.id/tugas/3238332. Rumus bilangan eksponen
brainly.co.id/tugas/3572353. Contoh soal bilangan eksponen
brainly.co.id/tugas/46549299Detail JawabanMapel : MatematikaKelas : 10 SMAMateri : EksponenKata Kunci : Pangkat, Perkalian, PenjumlahanKode Mapel : 2Kode Kategorisasi : 10.2.1.1[tex]\huge \boxed{ \bf \purple{Xx} \red{B} \blue{e} \orange{a} \green{u} \blue{t} \red{i} \blue{f} \pink{u} \purple{l} \orange{G} \purple{i} \red{r} \blue{l} \purple{xX}}[/tex]
16. 11/2+9/2+-9/2+-11/2=
11/2 + 9/2 + (-9/2) + (-11/2) =
11/2 +9/2 - 9/2 -11/2 = 011/2 + 9/2 - 9/2 - 11/2
= (11 + 9 - 9 - 11)/2
= 0/2
= 0
17. 1. 2/100 × 9/2=2. 2/100÷ 9/2=
Jawaban:
1. 18/200 = 9/100 = 0,09
2. 4/900 = 1/225 = 0,0044
Jawaban:
1. (2÷100 × 9)÷2 = 0,09
2.( 2÷ 100) ÷ (9÷2) = 0.00444444444
18. ×2-6×+2=10×2-6×=-2×2_6×+9=-2+9
soal apaan..................
19. √4+√4+√4+√4+......= √2+√2+√2+√2+......= √9+√9+√9+√9+......=
√4 = 2 --> 2x2 = 4 √9 = 3 ---> 3x3 = 9
jadi,
√4 +√4 +√4 +√4 = 2 + 2 + 2 + 2 =8
√2 +√2 +√2 +√2 = √4 +√4 = 2 + 2 = 4
√9 +√9 +√9 +√9 = 3 + 3 + 3 + 3 =12
[tex]\sqrt{4+\sqrt{4+\sqrt{4+\sqrt{4+\sqrt{...}}}}}=a\\(\sqrt{4+\sqrt{4+\sqrt{4+\sqrt{4+\sqrt{...}}}}})^2=a^2\\4+\sqrt{4+\sqrt{4+\sqrt{4+\sqrt{...}}}}=a^2\\4+a=a^2\\0=a^2-a-4\\\\a_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a_{1,2}=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(-4)}}{2(1)}\\a_{1,2}=\frac{1\pm\sqrt{1+16}}{2}\\a_{1}=\frac{1+\sqrt{17}}{2}(\text{ambil yang positif})\\\text{ atau }\\a_{2}=\frac{1-\sqrt{1+16}}{2}\\\\\boxed{HP=\{\frac{1+\sqrt{17}}{2}\}}[/tex]
[tex]\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{...}}}}}=b\\(\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{...}}}}})^2=b^2\\2+\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{...}}}}=b^2\\2+b=b^2\\0=b^2-b-2\\0=b^2-2b+b-2\\0=b(b-2)+1(b-2)\\0=(b+1)(b-2)\\\\b+1=0\\b=-1\\\\\text{atau}\\\\b-2=0\\b=2(\text{pilih yang positif})\\\\\boxed{HP=\{2\}}[/tex]
[tex]\sqrt{9+\sqrt{9+\sqrt{9+\sqrt{...}}}}=c\\(\sqrt{9+\sqrt{9+\sqrt{9+\sqrt{...}}}})^2=c^2\\9+\sqrt{9+\sqrt{9+\sqrt{...}}}=c^2\\9+c=c^2\\0=c^2-c-9\\\\c_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\c_{1,2}=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(-9)}}{2(1)}\\c_{1,2}=\frac{1\pm\sqrt{1+36}}{2}\\c_{1,2}=\frac{1\pm\sqrt{37}}{2}\\\\c_{1}=\frac{1+\sqrt{37}}{2}(\text{ambil yang positif})\\\\\text{atau}\\\\c_{2}=\frac{1-\sqrt{37}}{2}\\\\\boxed{HP=\{\frac{1+\sqrt{37}}{2}\}}[/tex]
20. 2. Hasil dari 2 : 9) +2 per 9 bagi per 9
2÷9+2⁹÷9
2/9 + 2⁹÷9
2/9+512÷9
2/9+512/9
514/9 atau 57 1/9